A train goes back and forth between Town $A$ and Town $B$. It departs Town $A$ at time $0$ and then repeats the following:

-   goes to Town $B$, taking $X$ seconds;
-   stops at Town $B$ for $Y$ seconds;
-   goes to Town $A$, taking $X$ seconds;
-   stops at Town $A$ for $Y$ seconds.

More formally, these intervals of time are half-open, that is, for each $n = 0, 1, 2, \dots$:

-   at time $t$ such that $(2X + 2Y)n ≤ t < (2X + 2Y)n + X$, the train is going to Town $B$;
-   at time $t$ such that $(2X + 2Y)n + X ≤ t < (2X + 2Y)n + X + Y$, the train is stopping at Town $B$;
-   at time $t$ such that $(2X + 2Y)n + X + Y ≤ t < (2X + 2Y)n + 2X + Y$, the train is going to Town $A$;
-   at time $t$ such that $(2X + 2Y)n + 2X + Y ≤ t < (2X + 2Y)(n + 1)$, the train is stopping at Town $A$.

Takahashi is thinking of taking this train to depart Town $A$ at time $0$ and getting off at Town $B$. After the departure, he will repeat the following:

-   be asleep for $P$ seconds;
-   be awake for $Q$ seconds.

Again, these intervals of time are half-open, that is, for each $n = 0, 1, 2, \dots$:

-   at time $t$ such that $(P + Q)n ≤ t < (P + Q)n + P$, Takahashi is asleep;
-   at time $t$ such that $(P + Q)n + P ≤ t < (P + Q)(n + 1)$, Takahashi is awake.

He can get off the train at Town $B$ if it is stopping at Town $B$ and he is awake.  
Determine whether he can get off at Town $B$. If he can, find the earliest possible time to do so.  
Under the constraints of this problem, it can be proved that the earliest time is an integer.

You are given $T$ cases. Solve each of them.

Input is given from Standard Input in the following format:

```
$T$
$\rm case_1$
$\rm case_2$
$\hspace{9pt}\vdots$
$\rm case_T$
```

Each case is in the following format:

```
$X$ $Y$ $P$ $Q$
```

Print $T$ lines.  
The $i$-th line should contain the answer to $\rm case_i$.  
If there exists a time such that Takahashi can get off the train at Town $B$, the line should contain the earliest such time; otherwise, the line should contain `infinity`.

-   All values in input are integers.
-   $1 ≤ T ≤ 10$
-   $1 ≤ X ≤ 10^9$
-   $1 ≤ Y ≤ 500$
-   $1 ≤ P ≤ 10^9$
-   $1 ≤ Q ≤ 500$

20
infinity
1000000000999999999

Let [a,b) denote the interval a≤t<b.

In the first case, the train stops at Town B during [5,7),[19,21),[33,35),…, and Takahashi is awake during [7,13),[20,26),[33,39),…, so he can get off at time 20 at the earliest.