Problem9249--ABC293 —— D - Tying Rope

9249: ABC293 —— D - Tying Rope

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Time Limit : 1.000 sec  Memory Limit : 512 MiB

Description

### Problem Statement

There are $N$ ropes numbered $1$ through $N$. One end of each rope is painted red, and the other is painted blue.

You are going to perform $M$ operations of tying ropes. In the $i$-th operation, you tie the end of rope $A_i$ painted $B_i$ with the end of rope $C_i$ painted $D_i$, where `R` means red and `B` means blue. For each rope, an end with the same color is not tied multiple times.

Find the number of groups of connected ropes that form cycles, and the number of those that do not, after all the operations.

Here, a group of connected ropes $\lbrace v_0, v_1, \ldots, v_{x-1} \rbrace$ is said to form a cycle if one can rearrange the elements of $v$ so that, for each $0 \leq i < x$, rope $v_i$ is tied to rope $v_{(i+1) \bmod\ {x}}$.

Input

### Input

The input is given from Standard Input in the following format:

```
$N$ $M$
$A_1$ $B_1$ $C_1$ $D_1$
$A_2$ $B_2$ $C_2$ $D_2$
$\vdots$
$A_M$ $B_M$ $C_M$ $D_M$
```

Output

### Output

Print $X$ and $Y$ in this order, separated by a space, where $X$ is the number of groups of connected ropes that form cycles, and $Y$ is the number of those that do not.

Constraints

### Constraints

-   $1 \leq N \leq 2 \times 10^5$
-   $0 \leq M \leq 2 \times 10^5$
-   $1 \leq A_i, C_i \leq N$
-   $(A_i, B_i) \neq (A_j, B_j), (C_i, D_i) \neq (C_j, D_j)$ $(i \neq j)$
-   $(A_i, B_i) \neq (C_j, D_j)$
-   $N, M, A_i$, and $C_i$ are integers.
-   $B_i$ is `R` or `B`, and so is $D_i$.

Sample 1 Input

5 3
3 R 5 B
5 R 3 B
4 R 2 B

Sample 1 Output

1 2
There are three groups of connected ropes: {1}, {2,4}, and {3,5}.
The group of ropes {3,5} forms a cycle, while the groups of rope {1} and ropes {2,4} do not. Thus, X=1 and Y=2.

Sample 2 Input

7 0

Sample 2 Output

0 7

Sample 3 Input

7 6
5 R 3 R
7 R 4 R
4 B 1 R
2 R 3 B
2 B 5 B
1 B 7 B

Sample 3 Output

2 1

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