Problem7309--CodeChef DELISH - Dessert Wizard

7309: CodeChef DELISH - Dessert Wizard

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Time Limit : 1.000 sec  Memory Limit : 256 MiB

Description

It's finally summer in Chefland! So our chef is looking forward to prepare some of the best "beat-the-heat" dishes to attract more customers. He summons the Wizard of Dessert to help him with one such dish.

The wizard provides the chef with a sequence of N ingredients where the ith ingredient has a delish value of D[i]. The preparation of the dish takes place in two phases.

Phase 1 : The chef chooses two indices i and j and adds the ingredients i, i+1, ..., j to his dish. He also finds the sum of the delish value in this range i.e D[i] + D[i+1] + ... + D[j].

Phase 2 : The chef chooses two more indices k and l and adds the ingredients k, k+1, ..., l to his dish. He also finds the sum of the delish value in this range i.e D[k] + D[k+1] + ... + D[l].

Note that 1 ≤ i ≤ j < k ≤ l ≤ N.

The total delish value of the dish is determined by the absolute difference between the values obtained in the two phases. Obviously, the chef wants to maximize the total delish value for his dish. So, he hires you to help him.

Input

First line of input contains an integer T denoting the number of test cases. For each test case, the first line contains an integer N denoting the number of ingredients. The next line contains N space separated integers where the ith integer represents the delish value D[i] of the ith ingredient.

Output

Print the maximum delish value of the dish that the chef can get.

Constraints

1 ≤ T ≤ 50
2 ≤ N ≤ 10,000
-1,000,000,000 ≤ D[i] ≤ 1,000,000,000

Sample 1 Input

2
5
1 2 3 4 5
4
1 1 -1 -1

Sample 1 Output

13
4

Example case 1.
Chef can choose i = j = 1, k = 2, l = 5.
The delish value hence obtained is | (2+3+4+5) ? (1) | = 13 .

Example case 2.
Chef can choose i = 1, j = 2, k = 3, l = 4.
The delish value hence obtained is | ( ( ?1 ) + ( ?1 ) ) ? ( 1 + 1 ) | = 4 .

HINT

难度系数:1804
题目来源:CodeChef DELISH

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