Problem7025--ABC173 —— F - Intervals on Tree

7025: ABC173 —— F - Intervals on Tree

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Time Limit : 1.000 sec  Memory Limit : 256 MiB

Description

We have a tree with $N$ vertices and $N-1$ edges, respectively numbered $1, 2,\cdots, N$ and $1, 2, \cdots, N-1$. Edge $i$ connects Vertex $u_i$ and $v_i$.
For integers $L, R\ (1 \leq L \leq R \leq N)$, let us define a function f(L, R) as follows:
  • Let $S$ be the set of the vertices numbered $L$ through $R$.f(L,R) represents the number of connected components in the subgraph formed only from the vertex set $S$ and the edges whose endpoints both belong to $S$.
Compute $\sum_{L=1}^{N} \sum_{R=L}^{N} f(L, R)$.

Input

Input is given from Standard Input in the following format:
$N$
$u_1\ v_1$
$u_2\ v_2$
$\vdots$
$u_{N-1}\ v_{N-1}$

Output

Print $\sum_{L=1}^{N} \sum_{R=L}^{N} f(L, R)$.

Constraints

$1≤N≤2×10^5$
$1 \leq u_i, v_i \leq N$
The given graph is a tree.
All values in input are integers.

Sample 1 Input

3
1 3
2 3

Sample 1 Output

7
We have six possible pairs $(L, R)$ as follows:
  • For $L = 1, R = 1, S = \{1\}$ and we have $1$ connected component.
  • For $L = 1, R = 2, S = \{1, 2\}$ and we have $2$ connected components.
  • For $L = 1, R = 3, S = \{1, 2, 3\}$ and we have $1$ connected component, since $S$contains both endpoints of each of the edges $1, 2$.
  • For $L = 2, R = 2, S = \{2\}$ and we have $1$ connected component.
  • For $L = 2, R = 3, S = \{2, 3\}$ and we have $1$ connected component, since $S$ contains both endpoints of Edge $2$.
  • For $L = 3, R = 3, S = \{3\}$ and we have $1$ connected component.
The sum of these is $7$.

Sample 2 Input

2
1 2

Sample 2 Output

3

Sample 3 Input

10
5 3
5 7
8 9
1 9
9 10
8 4
7 4
6 10
7 2

Sample 3 Output

113

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