Problem3377--Shave Beaver!

3377: Shave Beaver!

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Time Limit : 2.000 sec  Memory Limit : 256 MiB

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Description

time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

The Smart Beaver has recently designed and built an innovative nanotechnologic all-purpose beaver mass shaving machine, "Beavershave 5000". Beavershave 5000 can shave beavers by families! How does it work? Very easily!

There are n beavers, each of them has a unique id from 1 to n. Consider a permutation a1,a2,...,an of n these beavers. Beavershave 5000 needs one session to shave beavers with ids from x to y (inclusive) if and only if there are such indices i1<i2<...<ik, that ai1=x, ai2=x+1, ..., aik-1=y-1, aik=y. And that is really convenient. For example, it needs one session to shave a permutation of beavers 1,2,3,...,n.

If we can't shave beavers from x to y in one session, then we can split these beavers into groups [x,p1], [p1+1,p2], ..., [pm+1,y] (x≤p1<p2<...<pm<y), in such a way that the machine can shave beavers in each group in one session. But then Beavershave 5000 needs m+1 working sessions to shave beavers from x to y.

All beavers are restless and they keep trying to swap. So if we consider the problem more formally, we can consider queries of two types:

  • what is the minimum number of sessions that Beavershave 5000 needs to shave beavers with ids from x to y, inclusive?
  • two beavers on positions x and y (the beavers ax and ay) swapped.

You can assume that any beaver can be shaved any number of times.

Input

The first line contains integer n − the total number of beavers, 2≤n. The second line contains n space-separated integers − the initial beaver permutation.

The third line contains integer q − the number of queries, 1≤q≤105. The next q lines contain the queries. Each query i looks as pi xi yi, where pi is the query type (1 is to shave beavers from xi to yi, inclusive, 2 is to swap beavers on positions xi and yi). All queries meet the condition: 1≤xi<yi≤n.

  • to get 30 points, you need to solve the problem with constraints: n≤100 (subproblem B1);
  • to get 100 points, you need to solve the problem with constraints: n≤3·105 (subproblems B1+B2).

Note that the number of queries q is limited 1≤q≤105 in both subproblem B1 and subproblem B2.

Output

For each query with pi=1, print the minimum number of Beavershave 5000 sessions.

Examples
Input
5
1 3 4 2 5
6
1 1 5
1 3 4
2 2 3
1 1 5
2 1 5
1 1 5
Output
2
1
3
5

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