Problem10930--ABC365 - A - Leap Year

10930: ABC365 - A - Leap Year

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Time Limit : 1.000 sec  Memory Limit : 512 MiB

Description

You are given an integer $Y$ between $1583$ and $2023$.

Find the number of days in the year $Y$ of the Gregorian calendar.

Within the given range, the year $Y$ has the following number of days:

-   if $Y$ is not a multiple of $4$, then $365$ days;
    
-   if $Y$ is a multiple of $4$ but not a multiple of $100$, then $366$ days;
    
-   if $Y$ is a multiple of $100$ but not a multiple of $400$, then $365$ days;
    
-   if $Y$ is a multiple of $400$, then $366$ days.

Input

The input is given from Standard Input in the following format:

```
$Y$
```

Output

Print the number of days in the year $Y$ as an integer.

Constraints

-   $Y$ is an integer between $1583$ and $2023$, inclusive.

Sample 1 Input

2023

Sample 1 Output

365

$2023$ is not a multiple of $4$, so it has $365$ days.

Sample 2 Input

1992

Sample 2 Output

366

$1992$ is a multiple of $4$ but not a multiple of $100$, so it has $366$ days.

Sample 3 Input

1800

Sample 3 Output

365

$1800$ is a multiple of $100$ but not a multiple of $400$, so it has $365$ days.

1600

366

$1600$ is a multiple of $400$, so it has $366$ days.

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