Problem10872--ABC158 - D - String Formation

10872: ABC158 - D - String Formation

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Time Limit : 1.000 sec  Memory Limit : 512 MiB

Description

Takahashi has a string $S$ consisting of lowercase English letters.

Starting with this string, he will produce a new one in the procedure given as follows.

The procedure consists of $Q$ operations. In Operation $i$ $(1 \leq i \leq Q)$, an integer $T_i$ is provided, which means the following:

  • If $T_i = 1$: reverse the string $S$.

  • If $T_i = 2$: An integer $F_i$ and a lowercase English letter $C_i$ are additionally provided.

    • If $F_i = 1$ : Add $C_i$ to the beginning of the string $S$.
    • If $F_i = 2$ : Add $C_i$ to the end of the string $S$.

Help Takahashi by finding the final string that results from the procedure.

Input

Input is given from Standard Input in the following format:

```
$S$
$Q$
$Query_1$
$:$
$Query_Q$
```

In the $3$\-rd through the $(Q+2)$-th lines, $Query_i$ is one of the following:

```
$1$
```

which means $T_i = 1$, and:

```
$2$ $F_i$ $C_i$
```

which means $T_i = 2$.

Output

Print the resulting string.

Constraints

-   $1 \leq |S| \leq 10^5$
-   $S$ consists of lowercase English letters.
-   $1 \leq Q \leq 2 \times 10^5$
-   $T_i = 1$ or $2$.
-   $F_i = 1$ or $2$, if provided.
-   $C_i$ is a lowercase English letter, if provided.

Sample 1 Input

a
4
2 1 p
1
2 2 c
1

Sample 1 Output

cpa

There will be $Q = 4$ operations. Initially, $S$ is a.

  • Operation $1$: Add p at the beginning of $S$. $S$ becomes pa.

  • Operation $2$: Reverse $S$. $S$ becomes ap.

  • Operation $3$: Add c at the end of $S$. $S$ becomes apc.

  • Operation $4$: Reverse $S$. $S$ becomes cpa.

Thus, the resulting string is cpa.

Sample 2 Input

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample 2 Output

aabc

There will be $Q = 6$ operations. Initially, $S$ is a.

  • Operation $1$: $S$ becomes aa.

  • Operation $2$: $S$ becomes baa.

  • Operation $3$: $S$ becomes aab.

  • Operation $4$: $S$ becomes aabc.

  • Operation $5$: $S$ becomes cbaa.

  • Operation $6$: $S$ becomes aabc.

Thus, the resulting string is aabc.

Sample 3 Input

y
1
2 1 x

Sample 3 Output

xy

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