You are given an integer $N$. Among the divisors of $N!$ $(= 1 \times 2 \times ... \times N)$, how many Shichi-Go numbers (literally "Seven-Five numbers") are there?

Here, a Shichi-Go number is a positive integer that has exactly $75$ divisors.

Note: When a positive integer $A$ divides a positive integer $B$, $A$ is said to a divisor of $B$. For example, $6$ has four divisors: $1, 2, 3$ and $6$.

Input is given from Standard Input in the following format:

```
$N$
```

Print the number of the Shichi-Go numbers that are divisors of $N!$.

-   $1 \leq N \leq 100$
-   $N$ is an integer.

0

There are no Shichi-Go numbers among the divisors of 9!=1×2×...×9=362880.

1

There is one Shichi-Go number among the divisors of 10!=3628800: 32400.